Freezing point depression occurs when the freezing point of a liquid is lowered by adding another compound on it. The freezing point of water is 0º, but it can be depressed by adding a solvent such as salt in our experiment. It's a
In our experiment we're going to add some sugar to 5 different test tubes (0,5/1/1,5/2/2,5 grams per test tube) and we will put them up in a salt ice mixture d beaker.
The equation that we will use later on to calculate the change in freezing point is:
Change in boiling point = Kc x molality
(AT: change in boiling p
(
(
The more solute added in H2O, lower freezing point it will have. So, what happens when we place the test tubes in a salt ice mixture beaker?
Adding salt to the beaker with ice causes a temperature drop that slows the melting rate and increases the freezing one. The final result is that the ice melts slowly after the addition of salt. Another point to take into consideration is that as more solute, more Objective: To investigate the relationship between the
In this experiment we will see how the change in freezing point of a solution lowers when more solute is added to water. When the molality of the solution is bigger, the freezing point decreases.
We're going to place all the test tubes when different measurements of sugar in a big beaker with some ice cubes and salt. As I said before, the freezing point of water freezes at 0ºC, however, it's going to be lowered when salt is added. This is because the freezing point of solutions is all lower than that of the pure solvent. The salt dissolves into the liquid water in the ice and lowers its freezing point. This is because adding the solute will disrupt the equilibrium, the salt molecules dissolve in the water, but do not pack easily into the molecules in the solid (ice), making the freezing point of water being lowered when salt is added.
When we add more sugar, (more
The first thin
After we calculate the moles, using the formula of
molality (m): molality = moles/ kg of solvent (water – 0.005kg). We need
to follow this process to get the molality of every sugar test tube.
0 g sugar in 5.0 g water – Pure water so à 0 mol /kg
0.5 g sugar in 5.0 g water – (0.5/342.30) /0.005=
0.001/0.005= 0.2 mol / kg
1.0 g sugar in 5.0 g water – (1.0/ 342-30) /0.005= 0.003/
0.005= 0.6 mol / kg
1.5 g sugar in 5.0 g water – (1.5/342.30) /0.005= 0.004/
0.005= 0.8 mol / kg
2.0 g sugar in 5.0 g water – (2.0/342.30) /0.005= 0.006/
0.005= 1.2 mol / kg
2.5 g sugar in 5.0 g water – (2.5/342.30) /0.005=
0.007/0.005= 1.4 mol / kg
Table:
Mass of sugar in solution
(g)
|
(
|
Attempt 1 - Freezing point (oC)
|
Attempt 2 - Freezing point (oC)
|
Average freezing point (oC)
|
Change in freezing point compared to pure water (oC)
|
0
|
0
|
- 0
|
- 0.6
|
0.3
|
-0.3
|
0.5
|
0.2
|
- 0.6
|
- 0.8
|
0.7
|
-0.37
|
1.0
|
0.6
|
- 0.3
|
- 0.1
|
0.2
|
-1.12
|
1.5
|
0.8
|
- 1.7
|
- 1.7
|
1.7
|
-1.49
|
2.0
|
1.2
|
- 2.0
|
- 2.2
|
2.1
|
-2. 23
|
2.5
|
1.4
|
- 2.9
|
- 2.5
|
2.7
|
-2.60
|
A point to take into consideration is the position of the table. The freezing point depression is negative, that's why the
According to the hypothesis and the background information
Evaluation (Discussing problems and suggesting improvements):
Generally, we think we worked well as a
group and we haven't committed big or notable errors that are lately seen in the
results. However, as in every lab experiment we had some strong and weak
points;
On one hand, there were few strong points such
as when calculating the temperature, we were aware that it remained constant
and didn't change and when we were sure about this, we took out the thermometer
form the cold or ice. Also, we were very precise at the time of
getting the correct measurements. We followed the measurements that were in the
method exactly as they were. We get the amount of water needed and all the
elements we needed to use. We were extremely careful in this part because in
other experiments, not taking perfectly and carefully the right measurements
caused a complete disaster and non-sense results.
On the other hand, during the experiment we had
some weak points. Having weak points in an experiment is normal because in the lab the 're involved lots of factors that makes it easier to get a
mistake. For, the next lab session we should learn about these small
mistakes and correct them:
Firstly, we had some problems, as we didn´t know when we had to take out the thermometer. We didn’t know when it had reached the freezing point, so we had to repeat it a few times. Then, the way of calculating the temperature with those thermometers and continuously taking out from the solution and putting again in, is not a very precise and accurate way of completing and getting the freezing point of a solution. That way, the results must vary from othergroups experiments and might not be as accurate as we wanted them to be.
Firstly, we had some problems, as we didn´t know when we had to take out the thermometer. We didn’t know when it had reached the freezing point, so we had to repeat it a few times. Then, the way of calculating the temperature with those thermometers and continuously taking out from the solution and putting again in, is not a very precise and accurate way of completing and getting the freezing point of a solution. That way, the results must vary from other
We could improve this weaks points for the next
lab session by finding a new method or way of calculating temperature. Maybe putting
the solution at a fridge or something that maintains constant the temperature
we need to reach, this is another easy and better way.
References:
Chemwiki.ucdavis.edu, (2015). Freezing Point Depression - Chemwiki. [
All-science-fair-projects.com,. (2015). Science Fair Projects - The effect of salt and sugar